<\/span><\/h3>\n\n\n\nNous allons d\u00e9cider du fait que les couleurs seront repr\u00e9sent\u00e9es par des lettres capitalis\u00e9es de l’alphabet latin: A, B, C, D, …<\/p>\n\n\n\n
Nous allons donc \u00e9crire une premi\u00e8re fonction qui retourne l’alphabet sur lequel s’appuyer pour g\u00e9n\u00e9rer une combinaison de couleurs \u00e0 trouver:<\/p>\n\n\n\n
from string import ascii_uppercase\n\ndef gen_colors(code_size):\n if code_size <= 26:\n return ascii_uppercase[:code_size]\n else:\n return ascii_uppercase<\/pre>\n\n\n\nCette fonction retourne donc les n<\/em> premi\u00e8res lettres de l’alphabet si n<\/em>< 27, et retourne l’alphabet complet si n<\/em> > 26.<\/p>\n\n\n\n>>> gen_colors(5)\n'ABCDE'\n>>> gen_colors(200)\n'ABCDEFGHIJKLMNOPQRSTUVWXYZ'<\/code><\/pre>\n\n\n\nIl nous faut maintenant une fonction retournant une combinaison al\u00e9atoire de n<\/em> couleurs prises parmi toutes celles de ce nouvel ensemble.<\/p>\n\n\n\nfrom random import choice\ndef gen_code(code_size, colors):\n r = ''\n for _ in range(code_size):\n r += choice(colors)<\/pre>\n\n\n\n>>> gen_code(5,'ABCDEFGH')\n'GCBAG'<\/code><\/pre>\n\n\n\n<\/span>V\u00e9rifications<\/span><\/h3>\n\n\n\nNous allons dans un premier temps \u00e9crire une fonction check_guess(guess, code_size, colors)<\/span> qui v\u00e9rifie si, d’une part, la longueur de “guess” est la m\u00eame que code_size, et d’autre part si une couleur pr\u00e9sente dans “guess” est aussi dans “colors”:<\/p>\n\n\n\ndef check_guess(guess, code_size, colors):\n present_colors = [ i in colors for i in guess ]\n return len( guess ) == code_size and False not in present_colors<\/pre>\n\n\n\nJ’ai opt\u00e9 pour cette solution, mais il y a d’autres possibilit\u00e9s.<\/p>\n\n\n\n
Ici, je construis une liste de bool\u00e9ens correspondants au fait que chaque \u00e9l\u00e9ment de “guess” se trouve ou non dans “colors”. Si il n’y a aucun “False” dans cette liste, cela signifie que toutes les couleurs propos\u00e9es sont dans l’alphabet autoris\u00e9.<\/p>\n\n\n\n
Si la longueur de “guess” est la m\u00eame que celle de “colors” ET si aucun “False” est dans la liste construite, la fonction renvoie “True”.<\/p>\n\n\n\n
<\/span>Renvoi du nombre de bonnes couleurs <\/span><\/h3>\n\n\n\ndef score_guess(code, guess):\n n_good_position = 0\n n_false_position = 0\n if len( code ) == len( guess ):\n for i in range( len(code) ):\n if code[i] == guess[i]:\n n_good_position += 1\n elif guess[i] in code:\n n_false_position += 1\n \n return n_good_position , n_false_position<\/pre>\n\n\n\n>>> score_guess('ABCD' , 'AABC')\n(1, 3)<\/code><\/pre>\n\n\n\nIl y a en effet 1 bonne lettre (\u00e0 sa place) et en tout 3 lettres correctes mais pas \u00e0 la bonne place (le second ‘A’ est \u00e0 la deuxi\u00e8me position et non \u00e0 la 1\u00e8re, le ‘B’ et le ‘C’ sont bonnes mais pas au bon endroit).<\/p>\n\n\n\n
<\/span>Le jeu<\/span><\/h3>\n\n\n\ndef play(code_size, nb_colors):\n print(f'Les diff\u00e9rentes couleurs possibles sont: {gen_colors(nb_colors)}.')\n print(f'Le code \u00e0 trouver est de longueur {code_size}.')\n n = 0\n to_find = gen_code(code_size, gen_colors(nb_colors)) # combinaison \u00e0 trouver\n while True:\n guess = input(f'{n} --> ').upper()\n if not check_guess(guess, code_size, gen_colors(nb_colors)):\n print('Mauvaise taille ou couleur...')\n elif guess != to_find:\n print( score_guess(to_find, guess) )\n n += 1\n else:\n print( f'F\u00e9licitations, vous avez trouv\u00e9 apr\u00e8s {n+1} essais!' )\n break<\/pre>\n\n\n\n>>> play(4,4)\nLes diff\u00e9rentes couleurs possibles sont: ABCD.\nLe code \u00e0 trouver est de longueur 4.\n0 --> ABCD\n(1, 2)\n1 --> ABBB\n(0, 1)\n2 --> CBCC\n(1, 2)\n3 --> BBDD\n(1, 1)\n4 --> DBCB\n(0, 2)<\/code><\/pre>\n\n\n\nBon, je ne sais pas pour vous mais c’est assez frustrant de ne pas trouver apr\u00e8s un certain nombre d’essais.<\/p>\n\n\n\n
Je vais donc ajouter un argument \u00e0 ma fonction pour limiter le nombre de coups maximum.<\/p>\n\n\n\n
def play(code_size, nb_colors , nb_max = None):\n print(f'Possible colors are: {gen_colors(nb_colors)}.')\n print(f'Code size is {code_size}.')\n n = 0\n count = 0\n to_find = gen_code(code_size, gen_colors(nb_colors)) # combinaison \u00e0 trouver\n while True:\n if nb_max != None and n <= nb_max or nb_max == None:\n guess = input(f'{n} --> ').upper()\n if not check_guess(guess, code_size, gen_colors(nb_colors)):\n print('Mauvaise taille ou couleur...')\n elif guess != to_find:\n print( score_guess(to_find, guess) )\n n += 1\n else:\n print( f'F\u00e9licitations, vous avez trouv\u00e9 apr\u00e8s {n+1} essais!' )\n break\n else:\n print(f'Il fallait trouver: {to_find}')\n break<\/pre>\n\n\n\n>>> play(4,4,3)\nPossible colors are: ABCD.\nCode size is 4.\n0 --> aaaa\n(1, 3)\n1 --> bbbb\n(1, 3)\n2 --> cccc\n(1, 3)\n3 --> abcd\n(1, 3)\nIl fallait trouver: DACB<\/code><\/pre>\n\n\n\n<\/span>M\u00e9morisation des propositions<\/span><\/h3>\n\n\n\nDans la pratique, il est possible de s’y perdre avec toutes les propositions que l’on a faites.<\/p>\n\n\n\n
Si l’on souhaite ne pas compter les coups identiques, on peut m\u00e9moriser tous les coups dans une liste L.<\/p>\n\n\n\n
def play(code_size, nb_colors , nb_max = None):\n print(f'Possible colors are: {gen_colors(nb_colors)}.')\n print(f'Code size is {code_size}.')\n n = 0\n count = 0\n to_find = gen_code(code_size, gen_colors(nb_colors)) # combinaison \u00e0 trouver\n L = []\n while True:\n if nb_max != None and n <= nb_max or nb_max == None:\n guess = input(f'{n} --> ').upper()\n if not check_guess(guess, code_size, gen_colors(nb_colors)):\n print('Mauvaise taille ou couleur...')\n elif guess in L:\n print('Proposition d\u00e9j\u00e0 faite avant...')\n elif guess != to_find:\n print( score_guess(to_find, guess) )\n L.append( guess )\n n += 1\n else:\n print( f'F\u00e9licitations, vous avez trouv\u00e9 apr\u00e8s {n+1} essais!' )\n break\n else:\n print(f'Il fallait trouver: {to_find}')\n break<\/pre>\n\n\n\n>>> play(4,4,3)\nPossible colors are: ABCD.\nCode size is 4.\n0 --> abcd\n(0, 4)\n1 --> abcd\nProposition d\u00e9j\u00e0 faite avant...\n1 --> aabb\n(0, 4)\n2 --> bbbb\n(1, 3)\n3 --> dcba\n(2, 2)\nIl fallait trouver: BCDA<\/code><\/pre>\n\n\n\nBon, l\u00e0, on est pas mal non ?<\/p>\n","protected":false},"excerpt":{"rendered":"
Nous allons voir comment impl\u00e9menter un MasterMind en Python, mais uniquement en mode console.<\/p>\n","protected":false},"author":1,"featured_media":7499,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"class_list":["post-7498","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-python"],"yoast_head":"\n
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<\/figure>\n<\/div>\n\n\n\n\n\n\n